2X^2+(29/20)x-(3/10)=0

Solution for 2X^2+(29/20)x-(3/10)=0 equation:

2X^2+(29/20)X-(3/10)=0


Domain of the equation: 20)X!=0

X!=0/1

X!=0

X∈R


We add all the numbers together, and all the variables

2X^2+(+29/20)X-(+3/10)=0

We multiply parentheses

2X^2+29X^2-(+3/10)=0

We get rid of parentheses

2X^2+29X^2-3/10=0

We multiply all the terms by the denominator


2X^2*10+29X^2*10-3=0

Wy multiply elements

20X^2+290X^2-3=0

We add all the numbers together, and all the variables

310X^2-3=0

a = 310; b = 0; c = -3;
Δ = b2-4ac
Δ = 02-4·310·(-3)
Δ = 3720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3720}=\sqrt{4*930}=\sqrt{4}*\sqrt{930}=2\sqrt{930}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{930}}{2*310}=\frac{0-2\sqrt{930}}{620}
=-\frac{2\sqrt{930}}{620}
=-\frac{\sqrt{930}}{310}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{930}}{2*310}=\frac{0+2\sqrt{930}}{620}
=\frac{2\sqrt{930}}{620}
=\frac{\sqrt{930}}{310}
$